DM> I've decided I should have studied more 30 years ago ;-)
DM> Imagine a number of capacitors with one plate in common
DM> | To +DCV
DM> _______________|_________________________
DM> ____ ____ ____ ____ ____ ____
DM> | | | | | |
DM> Each one with a resistor in series (including a small resistor in
DM> series with the common). If I pull 2 capacitors down and two up (i.e.
DM> short them) at the same time, then the two being charged seem to
DM> charge a lot faster. Is ther any good reason why this is so, and can it
DM> be calculated? The capacitors are large, and most are equally sized.
DM> For the curious, the model above is based on a device being researched
DM> locally and is stripped of any unnecessary complications.
Hi Declan,
depending on the exact design you are talking about, you most probably
have a charging current flow between the minor plates being charged to
opposite potentials. The common plate will act as the connection and
thus the minor capacitors will appear as effectively being coupled in
series - dividing the effective capacitance.
A A
| || | ||
------- = B-||-o-||-C
--- --- || ||
| |
B C
Uwe.
--
Author: Uwe Zimmermann
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