John -
On Thu, Aug 27, 2009 at 04:59:45PM -0600, John Regehr wrote:
> > unsigned long a;
> > unsigned long *p;
> > p = (unsigned long *)&p;
> > a = ++(*p);
>
> Gabriel, since p refers to itself this code looks to me like an
> occurrence of the second clause of this type of undefined behavior:
>
> "Between two sequence points, an object is modified more than once, or
> is modified and the prior value is read other than to determine the
> value to be stored."
For folks like me, you should have added
that the sequence points in the code snippet
above are at the semi-colons. :-)
Once again I tripped over the *wrong* conception
that the assignment operator implies a sequence
point.
THX,
Chris
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