Oh, indeed!
char c = '.';
becomes
char c = (char)'.';
Thanks and sorry for the noise.
Marco
On 22.06.2010 11:16, Pascal Cuoq wrote:
> Hello,
>
> On Jun 22, 2010, at 11:13 AM, Marco Trudel wrote:
>> void foo(int i, char c) {
>> foo('.', 2);
>> i = c;
>> c = i;
>> }
>>
>> becomes:
>>
>> void foo(int i, char c) {
>> foo('.', (char)2);
>> i = (int)c;
>> c = (char)i;
>> }
>>
>> Where I guess the call to foo should be "foo((int)'.', (char)2);".
>
> I don't think it should.
>
> C99, 6.4.4.4, paragraph 10:
>
> An integer character constant has type int.
>
> Best regards,
>
> Pascal
>
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