I know (I better, as I'm about to take Switching 2.0). What I meant was that a physical ring would be something like a physical bus, where the two ends are connected together, thus forming a ring. Actually, it isn't, but it serves as example. I think FDDI has a true physical ring as a possibility.
 
Francisco Muniz
"Joel Studtmann" <[EMAIL PROTECTED]> escribi� en el mensaje de noticias 8kkakq$u33$[EMAIL PROTECTED]">8kkakq$u33$[EMAIL PROTECTED]...
10Base5 and 10Base2 (coax), are run in both a physical and logical bus.  A physical bus is NOT a physical ring.  In a ring, the two ends are connected to each other.  With 10Base2, both ends have a 50 ohm terminator (one grounded).
 
Ethernet (as well as token ring) use a physical star topology. There's a center (the hub, switch, or MAU) and a series of spokes attached to it. I think a physical implementation of a ring would be like an old style ethernet ("bus style" - 10base5 I think) where the last computer connects to the first, wouldn't it? What do you think?
 
Francisco Muniz.
I was reading about network topology and they say that an example of bus topology is Ethernet network. Wouldn't ethernet network be a ring topology due to
hub/switch environment?
 
Please correct me where I am wrong.
 
Thank you in advance.
 
Oscar Rau
 

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