Thank everybody for your help.
Finally I cleared the pain in the neck about Tcp/ip.
I tried to understand 172.37.2.56/12 with default subnet classful concept,
which wouldn't apply here.

Thanks all

jeongwoo

P.S: Thanks Koen, Larry!!
------Original Message------
From: "Koen&Beth" <[EMAIL PROTECTED]>
To: jeongwoo park <[EMAIL PROTECTED]>
Sent: July 14, 2000 6:05:09 AM GMT
Subject: RE: Tcp/ip question


No that's not correct
You can have a class B with subnet mask 255.252.0.0 but that's supernetting
and alot more complicated then subnetting.  It usually the last byte of the
default that's used to supernet  so 172.37.2.56/8  could be a supernet but I
doubt it that it would be used
I'm still a bit confused with that 172.37.2.56/8 to /20 because the class B
default is /16 (255.255.0.0).  So if it was supernetting then it would be
something like /14 but then it would say in the question otherwise it can be
a class B with default subnet mask but still with 14 bits borrowed to make
255.255.255.252 wich you can use in WAN links so you don't lose a lot of
hosts but then you have to use a Routing Protocol that can handle variable
subnet masks)
Hope this will cleared the confusion
Koen

-----Original Message-----
From: jeongwoo park [mailto:[EMAIL PROTECTED]]
Sent: Friday, 14 July 2000 15:08
To: Koen&Beth
Subject: RE: Tcp/ip question


hi Koen
What i meant by class B, subnet mask without default, 12 extended bit
was that 172.37.2.56/20 is class B and it can be a form that 172.37.2.56/8
has been subnetted to 172.37.2.56/20 by increasing bits from /8 to /20 (so,
12 bits was borrowed).
I understand that 172.37.2.56/20 is the form that class B default subnet 16
has been subnetted to /20 starting counting after default subnet. This part
was surely understood and it made perfect sense.
Could I consider that when I saw 172.37.2.56/20, it is the address that was
subnetted from 172.37.2.56/8?
I was very confused with this two concepts.
One is completely correct. But could you say that the other one is also
correct?


jeongwoo

------Original Message------
From: "Koen&Beth" <[EMAIL PROTECTED]>
To: jeongwoo park <[EMAIL PROTECTED]>
Sent: July 14, 2000 2:29:20 AM GMT
Subject: RE: Tcp/ip question


This is a 8 + 8 + 4
So Class B, default subnet + 4 masked bits = 255.255.240.0)
What do you mean with this: class B, subnet mask without default, 12
extended bits?
Class A default subnet is 255.0.0.0  or 8 + 0 + 0 + 0 (bits)
Class B 255.255.0.0 or 8 + 8 + 0 + 0 (bits)
Class C 255.255.255.0 or 8 + 8 + 8 + 0 (bits)
Koen

-----Original Message-----
From: jeongwoo park [mailto:[EMAIL PROTECTED]]
Sent: Friday, 14 July 2000 13:54
To: [EMAIL PROTECTED]; Koen&Beth
Subject: RE: Tcp/ip question


Thanks for your reply Koen
I guess now I got it.
Just one more question. can I?
let's say there is ip address: 172.37.2.56/20
How could I tell whether it is (class B, subnet mask with default, 4
extended bits), or (class B, subnet mask without default, 12 extended bits)?

I will appreciate your help.

jeongwoo


------Original Message------
From: "Koen&Beth" <[EMAIL PROTECTED]>
To: jeongwoo park <[EMAIL PROTECTED]>
Sent: July 14, 2000 12:56:52 AM GMT
Subject: RE: Tcp/ip question


I forgot to say how I remembered it
If I saw a Class B IP Address and it had a /x less then 16 then x would
represent the subnet mask bits without the default ones.  If on the other
hand x > 16 it would have the subnet masks bits in there for a Class B.
Class A x>8, Class C x>24
Hope this helped aswell
Koen

-----Original Message-----
From: jeongwoo park [mailto:[EMAIL PROTECTED]]
Sent: Friday, 14 July 2000 12:37
To: Koen&Beth
Subject: Re: Tcp/ip question


hi

172.37.2.56/12 means class B with subnet mask 12. right?
Then is it going to be 11111111.11111111.11111111.1111000
or
11111111.11110000.00000000.00000000?
Which one is correct?

Help me please.
Thanks.

------Original Message------
From: "Koen&Beth" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Sent: July 13, 2000 11:28:12 PM GMT
Subject: Re: Tcp/ip question


Hi
/12 means 12 subnet mask bits.  Don't count the default ones
In Binary it would be like this

172.37.2.56  = class B
Default for class B = 255.255.0.0 (11111111.11111111.0.0)
/12 in binary is = 11111111.11111111.11111111.1111000
decimal = 255.255.255.240

Hope this helped

Koen

<[EMAIL PROTECTED]> wrote in message news:<8kli4l$80n$[EMAIL PROTECTED]>...
> Hi!
> I am still struggling with Tcp/ip.
> Can I ask a question?
> Is 172.37.2.56/12 right formula?
> I am asking this question because I thought that once 172.37.2.56/12 is
> class
> B, it cannot have /12. Shouldn't it be allowed to use subnet mask
> starting
> from /18 to /30?
> This way, class A can have subnet mask starting from /10 to /30, and
> class C
> can have subnet mask starting from /26 to /30.
> This is what I have understood.
> Am I missing something?
> I will appreciate your reply.
>
> jeongwoo
>
>
> Sent via Deja.com http://www.deja.com/
> Before you buy.


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