I'd like to answer this to the group as well because it's an important distinction.  
From CCO, 
http://www.cisco.com/univercd/cc/td/doc/cisintwk/idg4/nd2003.htm#xtocid1338311

a few paragraphs in: 
<Begin copy>

Figure 3-6: DUAL feasible successor. 

[graphic on page - check it out, it's important to the example]

If Router B becomes unavailable, Router A will go through the following three-step 
process to find a feasible successor for Network 7:

Step 1 Determining which neighbors have an advertised distance to Network 7 that is 
less than Router A's feasible distance (FD) to Network 7. The FD is 31 and Router H 
meets this condition. Therefore, Router H is a member of V1.

Step 2 Calculating the minimum computed cost to Network 7. Router H provides a cost of 
40, and Router D provides a cost of 230. Dmin  is, therefore, 40.

Step 3 Determining the set of neighbors that are in V1 whose computed cost to Network 
7 equals Dmin  (40). Router H meets this condition.
<End copy>

This is an explanation in the section on the topology database & what happens when a 
route fails - if equal-cost load balancing & the route isn't the same cost, it 
wouldn't be used, BUT it would be in the topology database as a feasible successor - 
that allows it to be used immediately upon failure of the best route without a new 
calculation.

And the feasible successors are the possible routes for unequal cost, as long as their 
cost divided by the cost of the best route is less than or equal to the variance.

In step 1, feasible distance is total cost from current router to destination (is 
Arizona to Florida); advertised distance is cost from next possible hop to destination 
(is Kansas to Florida).

It is the same as your explanation below, however when they say current router, that 
is your starting point in my analogy - even if the packet started somewhere before 
that, once it's in the router, as far as that router is concerned it's the starting 
point.  The router doesn't care where the packet has been, only where it's going (of 
course policy routing is an exception to that, but wasn't part of this discussion!!).


>>> <[EMAIL PROTECTED]> 09/12 5:08 PM >>>

Hi Roger,

Thanks so much for answering my email :o)

I'm rather confused about the first condition as the BSCN course notes says: "A
route is feasible if the next router in the path is closer to the destination
than the current router", using your analogy, isn't that saying that you
consider Kansas only when it's closer to Florida than Texas is, not when you
can't use Texas?

Thanks
Helena







The first condition is used in either unequal OR equal cost load balancing.  It
is to prevent routing loops.  Think of it like this:  Let's say I'm going on
vacation.  I'm in Arizona. I want to get to Florida.  I can go thru Texas, which
is my best route, and there is a certain distance from California to Florida.
If I can't get thru Texas becauuse all the roads are closed.  My options are to
go thru Kansas or California.  Kansas is closer to Florida than Arizona, so it
fits the rules & I will consider it.  California is further from Florida than
Arizona is, so I won't consider it.  If I went thru California, once I got there
the gas station attendant would tell me to go thru Arizona, and I would drive in
a loop forever.

Notice this is comparing total distance of best route (from source to
destination) with advertised distance of alternate routes (from next hop to
destination).

The second condition is how much difference in total distances should I
tolerate.  Same analogy as above - If I am doing equal cost load balancing, The
total distance from Arizona - Texas - Florida is shorter than from Arizona -
Kansas - Florida, so I and my buddy will both drive thru texas.  If I am doing
unequal cost, the variance tells me how much different the alternatives can be
from the best (as a multiple of the best).

Notice here we are comparing total distance of the best router to total distance
of alternate routes.

Now the only thing beyond that is to remember that unlike in driving, the
hop-by-hop metrics in EIGRP are not calculated ina totally additive fashion -
rather it's lowest bandwidth on a link in the path (which is not additive) plus
total delay (which is additive).

>>> Helena <[EMAIL PROTECTED]> 09/12 12:46 AM >>>
Hi everyone,

CAn someone please explain the two feasibility conditions in EIGRP
unequal-cost load balancing?

They are:
- local best metric > best metric learned from the next router

- the "multiplier" x Local bestmetric for the destination > metric through
the next router

Thanks in advance
Helen

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