I feel the summarized supernet route should be 172.16.1.0/22
from the below fig ..its clear that the no of common bits in the MSB part is
22
|
If you expand 172.16.1.0 in bin ----->10110110.00010000.000000 |01.00000000
172.16.2.0 in bin------>10110110.00010000.000000
|10.00000000
172.16.3.0 in bin------>10110110.00010000.000000
|10.00000000
|
Thanks
Thangavel
----- Original Message -----
|
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Thursday, October 19, 2000 3:57 AM
Subject: Re: Summarization
> In a message dated 10/19/00 4:33:48 AM Eastern Daylight Time,
> [EMAIL PROTECTED] writes:
>
>
> > Hi All,
> >
> > There are 3 contiguous networks:
> > 172.16.1.0/24
> > 172.16.2.0/24
> > 172.16.3.0/24
> > What is the supernet ?
> > Is it 172.16.1.0/22 ? Would you pls explain to me ?
> >
> > TIA,
> >
>
> That is not the supernet because 172.16.2.0 does not have a common bit
place
> in 172.16.1.0/22. I believe that this would be superneted to
172.16.0.0/16.
> This is where I see them all matching up that is. It would be real hard
for
> me to explain this so I'll let someone else do that who is more
experienced
> with this. Hope I helped a little.
>
> Mark Zabludovsky ~ CCNA, CCDA, 1/4-NP
> <A HREF="mailto: [EMAIL PROTECTED]">[EMAIL PROTECTED]</A>
>
> "If you need luck, apparently you're not prepared...Go study!"
>
> ~Mark Zabludovsky~
>
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