Hi,
Just working my way through this quite excellent
paper at the moment by Galina Pildush.
Page 11, first paragraph (A4 - that is)
"the throughput of an OC-3 link (155Mbps)is
approximately 2.5 million cells per second."
155 * 10^6 = 155000000 bits per second.
155000000/8 = 19375000 bytes per second.
19375000/53 (48 payload + 5 byte header) = 365566
cells/second, approx 365 thousand cells/sec.
Conversely to achieve a throughput of 2.5 million
cells/second.
2.5 * 10^6 = 2500000 cells/sec
2500000 * 53 = 132500000 bytes/sec
132500000 * 8 = 1060000000 bits per sec
Thus requiring a Gigabit pipe.
Can someone check my logic ?
Regards,
Phil.
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