subtract the subnet mask from 255.255.255.255, then subtract 1 more
for your example, 255.255.255.255 minus 255.255.255.248 equals 7. subtract
one more and you get 6 hosts.
for a larger subnet, like 255.255.252.0, you'd get 3.255, which is 3*256+255
which is 1023. subtract one more and you get 1022
I guess you could use 255.255.255.254 as the base, too...
-e-
up wayyy too late
----- Original Message -----
From: paul
To:
Sent: Wednesday, July 11, 2001 3:11 AM
Subject: calculating allowable hosts [7:11902]
> Greetz,
> Can anyone explain how you get the allowable host addresses from the
> following 213.13.184.184 with 255.255.255.248?(or show where I can figure
> this out )
> Thanx
Message Posted at:
http://www.groupstudy.com/form/read.php?f=7&i=11909&t=11902
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