The number of packets in a queue on a packet-switching device increases
exponentially as utilization on the output port increases.
Queue depth = utilization/(1 - utilization)
So, do the math. If utilization is 90%, there will be more packets in the
queue than if utilization if 50%.
That's how I learned it, but it's probably more complex than this....
Comments, anyone else?
Thanks
Priscilla
At 10:41 AM 7/30/01, anil.philip wrote:
>Dear Priscilla,
>
>I have a small doubt. I think you are the best person to ask about. May be
>you think this as a stupid question. but this is making me crazy.
>
>If there is a serial link b/w two sites, at what point of % utilisation
>the response start degrading???
>
>Ideally if I have a T1 link, i shud get the same ping response time
>till the load on that link is 100%???
>
>When I say a T1, it is 1.55 M packets /s. So if the link is utilised for
>99% (say 1.50Mb..) still I have
>0.05 Mb left on that link and I shud be able to get a ping (32byte)
>response time, equivalent to 0% utilisation. Why the response time start
>degrading at some point of % utilisation??
>Let us assume there is no packet drop, memmory prob, enough buffer space
>etc....
>
>Request to do a REPLY ALL this email.
>
>
>Regds,
>Anil Philip
>AT&T Solutions.
>anil.philip
>e-mail: [EMAIL PROTECTED]
________________________
Priscilla Oppenheimer
http://www.priscilla.com
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