JimYam,

10.86.115.128 would be the "network" address if you are using a mask of
255.255.255.224.  Trying configuring the switch with 10.86.115.129.

Using a mask of 255.255.255.224 creates subnets of 32 addresses, of which
the first and last address in each subnet will be the network and broadcast
addresses respectively.

So:     10.86.115.0----10.86.115.31   1st subnet
        10.86.115.32---10.86.115.63   2nd subnet
        10.86.115.64---10.86.115.95     3rd subnet
        10.86.115.96---10.86.115.127    4th subnet
        10.86.115.128--10.86.115.159  5th subnet finally!

10.86.115.128 is the network address for your subnet and 10.86.115.159 is
the broadcast.  10.86.115.129-158 are your usable addresses.

Dave Swink

-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
JimYam
Sent: Monday, October 22, 2001 11:04 PM
To: [EMAIL PROTECTED]
Subject: Bad mask /27 [7:23844]


I have a Cat 2900XL. If I confg

"ip add 10.86.115.128 255.255.255.224" on VLAN 1, I will get an error of

"Bad mask /27 for address 10.86.115.128"

Have you encountered this problem and how can I fix it?

Thanks.




Message Posted at:
http://www.groupstudy.com/form/read.php?f=7&i=23851&t=23844
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