Great point.  It's not a supernet of anything.  Not with the first octet
being 24.

Thomas Larus


----- Original Message -----
From: "Paul Werner" 
To: ; "[EMAIL PROTECTED]" 
Sent: Saturday, October 27, 2001 4:02 PM
Subject: Re: Subject: Re: quick response (help) please [7:24238]


> Just as a clarification to what you wrote and the terminology
> that you used, how exactly are you defining a "Supernet,"
> particularly on this network?
>
> v/r,
>
> Paul Werner
>
> > I could be wrong here, but I would imagine the reason this
> works is that
> > you
> > have a supernet there, with the mask of 255.255.248.0, so the
> hosts
> > address
> > is not all-ones, so is not treated as a broadcast address.
> The host
> > address
> > includes 3 binary digits from the third octet (125), so it
> works out to
> > be
> > 101 11111111.  I guess that zero saves it from being a
> broadacst
> > address.
> >
> > Is this right, or did the Cable ISP just screw up?
> >
> > Thomas Larus
> > ""John Green""  wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > the IP address alloted by the dhcp server to my home
> > > computer (via cable ie cable modem connection) is
> > >
> > > IP address   24.15.125.255
> > > subnet mask  255.255.248.0
> > > def gw       24.15.125.1
> > >
> > > ok look ar the last quad .... it is 255 !!!
> > > i can't believe this.
> > >
> > > do you how this is possible ? 0 and 255 are rserved
> > > for network and broadcast addresses.....
> > >
> > > please email me asap...........
>
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