If the addresses you were assigned must be used for host addresses then VLSM
is the method. 160 addresses would require a block of 128 and a block of 32
addresses. The 48 requirement could be met with a block of 64. The 16 by 16.
The remainder could be used for serial links. Not all addresses could be
used for hosts as there is a need for subnet and broadcast addresses for
each block. The router interface will use an address from each block.
If it were necessary to put the 160 addresses on one interface then one
block could be assigned as a secondary ip address.

Another possibility would be to use RFC1918 addresses for the hosts and use
NAT to talk to the rest of the world.

> -----Original Message-----
> From: Andy Hutchinson [mailto:[EMAIL PROTECTED]]
> Sent: Friday, November 30, 2001 8:38 AM
> To: [EMAIL PROTECTED]
> Subject: Subnetting [7:27808]
> 
> 
> Can anyone help !
> I have been assigned by our Head Office a Class B address
> (Let's say 172.133.205.0) with a subnet mask of 255.255.255.0
> which gives me 254 hosts available.
> However i have to split this between 3 locations
> like so :
> 
> Loc A : Minimum Addresses Required 160 (HQ)
> Loc B : Minumum Addresses Required 16
> Loc C : Minumum Addresses Required 48
> 
> Loc B & C will each have a router that connects to a router at Loc A.
> 
> Any ideas on how this can done ?
> 
> Thanks
> 
> Andy Hutchinson




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