Yes, I believe that you have it... 192.168.50.0 255.255.255.128 host 1-126 192.168.50.128 255.255.255.128 host 129-254
Larry Letterman Cisco Systems [EMAIL PROTECTED] -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Hunt Lee Sent: Sunday, February 24, 2002 4:34 PM To: [EMAIL PROTECTED] Subject: Re: VLSM Question [7:35827] So does it mean on the first subent -> the host range is 192.168.50.1 - 192.168.50.126, and the second subnet host range is 192.168.50.129 - 192.168.50.254? Best Regards, Hunt Lee ""G Z"" wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > The 25 bit can be 0 or 1. It looks like the book chose 0. The CCNA books use > 2^n - 2 for both hosts and subnets. But you also can use the > zero and one subnet so that would add 2. Then you would have 2^n for > subnets. So, 192.168.50.0 is one, and 192.168.50.128 is another subnet. > Using the first subnet: 192.168.50.0 network > 192.168.50.00000001 first host > 192.168.50.01111110 last host > 192.168.50.11111111 broadcast > > I hope this helps and also that it's right. I just got my NA recently. Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=36355&t=35827 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
