Agreed!

Mike W.

"timothy thielen"  wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> The best way for me to understand is to do the binary, and let the
shortcuts
> go hang.  As someone once said to me "I'm not smart enough to do the
> shortcuts"
>
>
> Kage Roc wrote:
> >
> > I promise I will not be a knowledge leech, I will contribute
> > what I know as well.   Ofcourse I do have a question regarding
> > IP Summaization:   Up untill today I thought I had
> > summarization down cold until I tried a few self made
> > excercises.   The formula I used to gather a summ address was
> > 2n=x.  Thats 2 to the n power equals x.
> > x is the number of subnets that you want to summarize and n
> > will be how much you subtract from the lowest mask of those
> > subnets.  for example:
> >
> >
> > 216.52.146.136/30
> > 216.52.146.140/30
> > 216.52.146.144/30
> > 216.52.146.148/30
>
> you can only summarize to where the bits are identical.  Looking at the
last
> octet:
>
> 136=10001000
> 140=10001100
> 144=10010000
> 148=10010100
>
> the boundary would be at /27, the total of the first three octets and the
3
> bits of the fourth.  The summary route would be 216.52.146.128/27
>
> If you use /28 for those networks, you're gonna get something funky.
>
> >
> > using that formula the summ would be 216.52.146.136/28 which is
> > not a valid route. Hoever that formula works here:
> > 216.52.146.48/29
> > 216.52.146.56/29
> >
> > summ route: 216.52.146.48 /28
> >
>
> here the last octets are:
> 48=00110000
> 56=00111000
>
> making the masked bits /28 (3 octets + 4 identical bits)
>
> > I guess my question is, what is the best/effective/convient way
> > to derive summary addresses?  Thanks for any input.
> >
>
> If you're very lucky, you have the brain to do this silliness in your
head.
> Otherwise, just do the binary conversions and draw lines.
>
> --Tim, the pretty sure he got that right.




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