Tc = 1/8 of 1s by default. Therefore since you have 64000 as CIR, each TC can send 8k. If you send 4K, you still have another 4k to burst in that window. You can still send more, as most frame-switches police on 1 or 2 second intervals, so if you violate the Be for 1 or 2 Tc's it will even out ovet the 1 or 2 second interval.
-- RFC 1149 Compliant. ""Pierre-Alex Guanel"" wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Sorry for posting this again .... > > Please check my logic on this frame-relay traffic shaping scenario: > > My Bc is 8,000 bits > My Be is 16,000 bits > My CIR is 64 Kbps > > If I send 1 burst of 56,000 bits then 4 bursts of 4,000 bits, after the 4th > burst of 4,000 bits I will be able to burst again but not before that. > Correct? > > Here is my rational (Assume no congestion in the frame-relay network): > > During the first Tc interval, I send Bc+Be. > During the second, third and fourth interval I can no longer burst > because I have used all my "burst credit". > At the end of the 4th Tc interval I have taken care of my first burst. > > During the next four bursts, I am "paying back" so to speak on my credit > line because I am sending less than the CIR. > So on the 9th Tc interval I can burst again. > > > Pierre-Alex Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=46080&t=46076 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
