This can't be done neatly without given the various subnets a bunch of 
different networks.  R2 and R4 take up the full /22 given r2 needs a /23 
and R4 needs a /24.

At 02:53 PM 7/28/2002 +0000, crow wrote:
>Ahhhhhhhhhhh!! sorry: wrong numbers of hosts
>
>
>192.168.24.0/22
>                                            router1 (50 hosts)
>
>                     router2                router3                 router4
>                  (400 hosts)            (50 hosts)            (200 hosts)
>
>
>
>
>""crow""  schrieb im Newsbeitrag
>[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > hallo guys!!
> >
> > I am ashamed to ask you for this assistance but I despaired with my cidr
> > prob.
> > i have so many results and getting more and more confused.
> > here the task:
> >
> > 192.168.24.0/22
> >                                             router1 (28 hosts)
> >
> >
> >                   router2                router3                 router4
> >                  (60 hosts)            (12 hosts)            (12 hosts)
> >
> > router 1 is connected with 2, 3, and router4, each of the routers have a
> > number of hosts behind.
> >
> > Task:
> > Create an addressing scheme using VLSM.
> >
> > You are assigned the CIDR address 192.168.24.0/22 and must support the
> > network. You are not permitted to use ip unnumbered or nat on this
>network.
> > Create an addessing scheme that meets the requirements shown
> >
> > i know, that this is a simple question, but i have learned already 10
>hours
> > today, but cant solve that prob.
> > but i want to solve this prob today, so plz help me.
> >
> > thx in advanced
> > andy




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