""Keith Woodworth""  wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> simple question.
>
> want to write an ACL:
>
> access-list 100 permit ip 209.145.96.0 0.0.3.255 any
>
> just to make sure Ive got my bits right this will cover:
>
> 209.145.96.0/24
> 209.145.97.0/24


the "3" in the third octet is 11 in binary. 11 ( binary) covers what decimal
numbers?


>
> Is that right?
>
> Thanks,
> Keith




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