the rule is 5 hubs 4 segments and only 3 populated segments but the above only applies to 10base x the hall problem is the the round trip propagation that cannot exceed 512bit time, so for a 10base x, the maximun roud trip should be 51.2microsecs or less, other wise problems will manifest, by being unable to detect collision(csma-cd will fail)
""Tiongster"" a icrit dans le message de news: [EMAIL PROTECTED] > Hi to all pros, > > I would like to ask a very simple which is also very confusing. If I > connected three hubs together have I break a 5-4-3 rule? But I don't > think I have break the 5-4-3 rule because I believe the wiring of the > hub is a bus circuit which is a segment and with three hubs connected > together it consist of three segments. I hope someone will correct me if > I'm wrong as I have been debating with my peers for past few days. My > peers insisted four hubs connected is the correct one which is the > maximum network of the 5-4-3 rule. Aren't four hubs consist of four > segments which have broke the 5-4-3 rule? Thanks in advance. > > Chiam Chin Tiong CCNA > ITE Dover student > ICQ 153179194 > > [GroupStudy removed an attachment of type application/octet-stream which had > a name of image001.jpg] > > [GroupStudy removed an attachment of type application/octet-stream which had > a name of image001.jpg] Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=65166&t=65140 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
