The rest of the world has to have a route to your pool of addresses
(222.2.2.1-254 in your example). The pool is assigned by your local ISP.
They should have a route to it.
With PAT you could use the WAN interface address for all translations.

> -----Original Message-----
> From: James Gosnold [mailto:[EMAIL PROTECTED]
> Sent: Friday, March 21, 2003 8:55 AM
> To: [EMAIL PROTECTED]
> Subject: Confused over NAT [7:65926]
> 
> 
> Dear all,
> 
> Just having a slight problem getting my head around NAT regarding the
> example configurations in the study guides I have.
> 
> access-list 1 permit 10.0.0.1 0.0.0.255 (defines list of addresses)
> 
> ip nat pool mynatpool 222.2.2.1 222.2.2.254 netmask 
> 255.255.255.0 (defines
> pool of inside global addresses NAT can replace the SA with)
> ip nat inside source list 1 pool mynatpool (applies the 
> addresses laid out
> in the access-list as inside addresses and tells router to 
> replace SA from
> mynatpool)
> 
> int eth0
> ip address 10.0.0.1 255.255.255.0
> ip nat inside (tells NAT that this is where inside addresses 
> come from)
> 
> int ser0
> ip address 133.4.4.1 255.255.255.0
> ip nat outside
> 
> So here is my confusion: 
> 
> If the Ser0 interface is the WAN address (133.4.4.1) and it 
> replaces the
> inside local address with a SA from mynatpool (222.2.2.1 - 
> 222.2.2.254) then
> how will the packet get back to the WAN interface? I thought 
> that NAT would
> replace the inside local address with the address of the WAN 
> interface, not
> a group of different public ip addresses? How will the packet 
> get back if
> the SA is from the range 222.2.2.1 - 254 and yet the IP 
> address of the WAN
> interface is clearly not from this range?
> 
> Confused from London....
> 
> Regards, James.




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