Thanks for the tip!
On 9/10/07, Joe Ciccone <[EMAIL PROTECTED]> wrote:
>
> David Whitney wrote:
> > Hello,
> >
> > I am writing a Makefile to build glibc in Chapter 10 of the CLFS
> > guide. I am trying to setup something like the following:
> >
> > ARCH = `cut -d- -f1 <<< ${MACHTYPE}`
> > CONFIG_ENV = CFLAGS="-march=$(ARCH) -mtune=generic -g -O2"
> >
> > When I am at the shell prompt and run this command, echo $MACHTYPE,
> > the result is i686-redhat-linux-gnu. When I run the Makefile to echo
> > $(ARCH), I receive this error:
> >
> > echo `cut -d- -f1 <<< `
> > /bin/sh: command substitution: line 0: syntax error near unexpected
> > token `newline'
> > /bin/sh: command substitution: line 0: `cut -d- -f1 <<< '
> >
> > I used a similar style way of defining ARCH when I built glibc for the
> > cross-tools, however in that case it was not MACHTYPE that was
> > referenced, but instead the CLFS_TARGET environment variable. How can
> > I get this latest Makefile to "see" MACHTYPE? I realize that MACHTYPE
> > is not an environment variable. Is there a work around (other than
> > hard-coding)?
> Some good reading would be the make info pages.
>
> Double up the $, so you get $$MACHTYPE. Otherwise make will treat
> ${MACHTYPE} as 2 entities "${""MACHTYPE}"
>
> On a side note, each time you reference $(ARCH) it's going to fork off a
> process and recalculate the value. If you use := to assign the value, it
> won't try to re-calculate it's value each time you reference it. Another
> thing you might want todo in combination with that is evaluate that
> result when you assign the value, so each time you reference $(ARCH) it
> doesn't fork off a process.
>
> ARCH := $(shell cut -d- -f1 <<< $$MACHTYPE)
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