Re: (clug-talk) PHP Object creation?

[Aaron J. Seigo]

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On Tuesday 19 August 2003 09:16, Jeffrey Clement wrote:
> An array would be the usual way to do this.   Makes it way easier to
> programmatically go through them all and do something to them.
>
> C++
> {
>     Car cars[30];
>     for(int i=0; i<30; i++)
>     {
>         cars[i] = new Car();
>     }
> }

well, personally, in C++ i'd use a vector, a queue, a deque or some other list 
template ... easier/safer to work with due to iterators and simplified memory 
management. attached is a fun bit of code that demonstrates this... compile 
it and try passing various numbers in to it as the first parameter (default 
is 10 if no params passed in)

using an array is much more C-ish. in C, if i knew exactly how many of that 
data structure i'd need i might use an array ... otherwise i'd make the 
struct a linked list...

> PHP is essentially the same.  

PHP is a lot less strict when it comes to array management and doesn't really 
offer anything much better to use, so using an array here isn't such a bad 
idea...

- -- 
Aaron J. Seigo
GPG Fingerprint: 8B8B 2209 0C6F 7C47 B1EA  EE75 D6B7 2EB1 A7F1 DB43
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#include <iostream>
#include <vector>
using namespace std;

class A
{
    public:
        A()
        {
            m_id = ++s_count;
        }

        A(const A&)
        {
            m_id = ++s_count;
        }

        int id() const
        {
            return m_id;
        }

        static int count()
        {
            return s_count;
        }

    private:
        static int s_count;
        int m_id;
};

int A::s_count = 0;

ostream& operator<< (ostream& stream, const A& a)
{
    stream << "I am A" << a.id() << " of " << A::count();
    return stream;
}


int main(int argc, char* argv[])
{
    int listLength = 10;

    if (argc == 2 && argv[1])
    {
        listLength = atoi(argv[1]);
        if (listLength < 1)
        {
            cerr << "C'mon, you have to specify 1 or more elements!" << endl;
            return 0;
        }
    }

    vector<A> aList(listLength);
    vector<A>::iterator it = aList.begin();

    for (; it != aList.end(); ++it)
    {
        cout << (*it) << endl;
    }

    return 0;
}