This is it! It seems to work correctly, when using cd instead of "cd .".
It seems I misinterpreted a command line parameter of a linker call as
the directory output. Sorry for the confusion.
I'm not exactly in love with Windows ;-)
Martin
David Cole wrote:
Try just "cd" -- cd . does not give any output at all, it's just a
no-op... cd without any arguments prints the current working directory
just like pwd...
On Fri, Jun 27, 2008 at 9:20 AM, Bill Hoffman
<[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>> wrote:
Martin Apel wrote:
Bill Hoffman wrote:
Martin Apel wrote:
Hi Brad,
this is kind of difficult under Windows, as far as I
know. I have MSys installed on my machine, but the pwd
"command" is not really a command (i.e. .exe) under
MSys, but a shell script, which invokes
the shell command "pwd". Windows sees the file with
the "pwd" command in C:\MSys\bin as an ordinary file,
not an executable. So I cannot call this from within
ADD_CUSTOM_COMMAND. As I am no Windows expert, I
haven't found any other way. Can you recommend a way,
how to do this?
cd .
Hi Bill,
this doesn't result in any output at all:
ADD_CUSTOM_COMMAND (COMMAND cd .
WORKING_DIRECTORY ${CMAKE_CURRENT_BINARY_DIR})
I think "cd ." cannot work, because there is no cd.exe under
Windows. I even tried "C:/WINNT/System32/cmd.exe /C cd .", but
this didn't work either.
It does work. The output is going to be in that html file that
visual studio creates when it does the build. I think you have to
cntrl-click to see it.
-Bill
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