This seems to be the recommended way to link against the zlib library:
find_package(ZLIB)if (ZLIB_FOUND)
include_directories(${ZLIB_INCLUDE_DIRS})
target_link_libraries(MyProg ${ZLIB_LIBRARIES})
endif()
When I run this on linux I see that ZLIB_LIBRARIES has the value
/usr/lib64/libz.so. On this machine gcc creates 64-bit binaries by
default. In my CMakeLists.txt I have an option for building 32-bit which
adds "-m32" to the compiler and linker command lines. However the
ZLIB_LIBRARIES variable is still returning the 64-bit version
(/usr/lib64/libz.so) instead of the 32-bit version (/usr/lib/libz.so).
Is there some way for me to let cmake know that I'm building 32-bit so that
the find_package(ZLIB) command sets ZLIB_LIBRARIES to the correct 32-bit
version of the library ?
--
Glenn
--
Powered by www.kitware.com
Please keep messages on-topic and check the CMake FAQ at:
http://www.cmake.org/Wiki/CMake_FAQ
Kitware offers various services to support the CMake community. For more
information on each offering, please visit:
CMake Support: http://cmake.org/cmake/help/support.html
CMake Consulting: http://cmake.org/cmake/help/consulting.html
CMake Training Courses: http://cmake.org/cmake/help/training.html
Visit other Kitware open-source projects at
http://www.kitware.com/opensource/opensource.html
Follow this link to subscribe/unsubscribe:
http://public.kitware.com/mailman/listinfo/cmake
