Hi all, Could someone give me a suggestion to avoid evaluation in parameters in a defun?
(defun foo (bbb) ... ) (foo bar) with this defun and this call bar is evaluated to avoid evaluation i need to call with (foo 'bar) What modification to the (defun foo ...) do I have to make to have bar not evaluated in (foo bar) ? Thanks in advance Jacques -- Dr. Jacques B. Siboni mailto:[EMAIL PROTECTED] 8 pass. Charles Albert, F75018 Paris, France Tel. & Fax: 33 (0) 1 42 28 76 78 Home Page: http://www.lutecium.org/jacsib/
