>If I declare the char * buf before calling open(...), it runs. >Else if I declare char * buf = new char after calling open(...), it runs >so.
>It seems strange, no ? Not strange at all, what you've just coded is a buffer overflow waiting to happen. You will need to use new/malloc to allocate the memory for the "char" you are pointing buf towards. Or define buf in a way that allocates space for it, instead of space for a pointer. ChrisB. _______________________________________________ cobalt-developers mailing list [EMAIL PROTECTED] http://list.cobalt.com/mailman/listinfo/cobalt-developers
