On Mon, 25 Mar 2013, Michael Stefaniuc wrote:
> Hello,
>
> is there an intrinsic way to get from a parameter list to an expression
> list? That would come in handy when forwarding from one function to
> another one. At the moment I help myself with a python rule that
> transforms the parameter list to an identifier but that feels clumsy.
> E.g. in SmPL pseudo code something like this would be nice:
>
> @@
> type T;
> parameter list P;
> expression list E = P;
> expression ret;
> @@
> T foo(P)
> {
> return
> - ret
> + bar(E)
> ;
> }
No, there is nothing. I guess your transformation gets rid of the types in
the parameter list? Perhaps what you would liek is a way to just match
the list of identifier parts?
julia
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