> If you have a->b->c->d->e, then eg b->c->d is not an expression.
I have got an other opinion here. * Can each part between the pointer access operators be an expression? * How long can such a structure member access chain become in interesting source codes? Regards, Markus _______________________________________________ Cocci mailing list [email protected] https://systeme.lip6.fr/mailman/listinfo/cocci
