--- Please note the new email address ---
On Wed, 19 Feb 2020, Ville Syrjälä wrote:
> Hi all,
>
> I was trying to do the following transformation:
> @@
> identifier M;
> expression E;
> @@
> - struct foo M = E;
> + struct foo M;
> + copy_struct(&M, &E);
>
> but without inserting the function call in the middle of the
> declarations and instead pushing it past them.
>
> This is one attempt:
> @decl@
> identifier M;
> expression E;
> @@
> - struct foo M = E;
> + struct foo M;
>
> @copy@
> identifier decl.M;
> expression decl.E;
> declaration D;
> statement S;
> @@
> struct foo M;
> ...
> D
> + copy_struct(&M, &E);
> S
>
> The copy rule fails to match anything when I have != 1
> declarations after the struct. So the ... doesn't seem
> to eat the extra declarations for some reason.
@copy@
identifier decl.M;
expression decl.E;
declaration D;
statement S;
@@
struct foo M;
... when any
D
+ copy_struct(&M, &E);
S
Otherwise, ... doesn't match code that includes what is before or after
it, ie struct foo M or D.
Aternatively:
@copy@
identifier decl.M;
expression decl.E;
declaration D;
statement S,S1;
@@
struct foo M;
... when != S1
+ copy_struct(&M, &E);
S
julia
>
> Also tried some other tricks with <... ...> but that just resulted
> in the code being inserted into every if block in the function.
> Not what I wanted.
>
> I guess what I might need is something along the lines of:
> @copy@
> ...
> declaration list[N] D;
> @@
> struct foo M;
> D
> + copy_struct(&M, &E);
> S
>
> but that's not supported it seems.
>
> Is there any way to achieve this atm?
>
> --
> Ville Syrjälä
> Intel
> _______________________________________________
> Cocci mailing list
> [email protected]
> https://systeme.lip6.fr/mailman/listinfo/cocci
>
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