> On 14 Dec 2015, at 00:18, Quincey Morris
> <[email protected]> wrote:
>
> On Dec 13, 2015, at 14:59 , Luc Van Bogaert <[email protected]
> <mailto:[email protected]>> wrote:
>>
>> I have a NSButton subclass that I want to conform to
>> NSValidatedUserInterfaceItem, so I can call validateUserInterfaceItem: on a
>> validator passing the button as a parameter. This requires my subclass to
>> implement two methods: action() and tag(). The compiler complains about the
>> selectors being identical to the 'action' and 'tag' selectors in superclass
>> NSControl.
>
> What do your subclass implementations look like (the signature, not the body)?
>
> According to the documentation, NSControl already has the conforming
> properties, so you don’t need to define your own. Just assign the correct
> values to the existing properties.
>
> However, the Swift version of NSValidatedUserInterfaceItem declares the
> properties as methods, so this may be confusing the issue. In Obj-C, it’s all
> the same thing — the getter for “action” is also the method “action”, but I’m
> not sure what happens during bridging. (It ought to realize they’re the same
> thing.)
>
> What happens if you *don’t* declare action and tag in your subclass? Is there
> a non-conformance warning?
I've defined the subclass like this:
class ValidatedButton: NSButton, ValidatedControl {
I've defined ValidatedControl like this:
protocol ValidatedControl: NSValidatedUserInterfaceItem {
This results in a compiler error: Type ValidatedButton does not conform to
protocol NSValidatedUserInterfaceItem.
I've tried overriding the NSControl properties 'action' and 'tag', but the
error remains.
--
Luc
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