> On 12 Sep 2016, at 14:27, Quincey Morris
> <[email protected]> wrote:
>
> On Sep 12, 2016, at 00:08 , Gerriet M. Denkmann <[email protected]> wrote:
>>
>> I want to do:
>> if self.dynamicType == SomeClass { … }
>>
>> But the compiler won’t accept this (or any number of variations thereof).
>
> Try this:
>
> if self is SomeClass { … }
>
> Typically, if you need to use a class in an expression, you’ll need to refer
> to the metatype instance:
>
> if self.dynamicType == SomeClass.self { … }
>
> but this would be an exact match. If you want the semantics of “isKindOf”
> (that is, the object is of the specified class or a subclass) then “is” is
> the way to go.
if self.dynamicType == SArray.self
{
print("Test1 \(self.dynamicType) is a subclass of SArray")
}
else
{
print("Test1 \(self.dynamicType) is NOT subclass of SArray")
}
prints: Test1 SArray2 is NOT subclass of SArray
Not quite what I expected.
But this works:
if self.dynamicType == SArray1.self || self.dynamicType == SArray2.self ||
self.dynamicType == SArray3.self
{
print("Test2 \(self.dynamicType) is a subclass of SArray")
}
else
{
print("Test2 \(self.dynamicType) is NOT subclass of SArray")
}
prints: Test2 SArray2 is a subclass of SArray
The only problem: It is kind of fragile. When I create a new class SArray5 then
I must remember to fix this test.
I would much prefer to have the semantics of “isKindOf”.
Kind regards,
Gerriet.
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