On Thu, Feb 5, 2009 at 4:52 PM, Iceberg-Dev <dev.iceb...@gmail.com> wrote:
> Problem:
> --------
>
> I would like to transform a NSString to a NSString conforming to the C
> string format.
>
> Examples:
> ---------
>
> toto -> toto
>
> "toto -> \"toto
>
> toto -> toto\ntiti
> titi
Well, first consider how you want to handle non-ascii characters. That
is, do you want your C string to be in a specific coding, like UTF8.
Then, I'd do something like this:
const char* cSource = [source cStringUsingEncoding:NSUTF8StringEncoding];
int i = 0, j = 0;
int cSourceLen = strlen( cSource );
char *cResult = NULL;
NSString *result = nil;
cResult = (char*)calloc( (cSourceLen * 4) + 1, 1 ); // max possible
for (i = 0; i < cSourceLen; ++i) {
if (isprint( cSource[ i ] )) {
cResult[ ++j ] = cSource[ i ];
} else {
switch (cSource[ i ]) {
case '\n':
strcpy( cResult[ j ], "\\n" );
j += 2;
break;
case '\t':
// etc for the all the other special cases
default:
sprintf( cResult[ j ], "\\x%02x", cSource[ i ] );
j += 4;
break;
}
}
}
result = [[NSString alloc] initWithBytesNoCopy:cResult length:j
encoding:NSASCIIStringEncoding freeWhenDone:YES];
That is 100% untested, btw. I have a meeting to go to :)
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