On Thu, Aug 20, 2009 at 2:01 PM, Clark Cox<[email protected]> wrote: > Yes, and two different objects will have different pointer values. If > the hash is based on the pointer values, then two different objects > cannot have the same hash, regardless of whether or not they are > equal. Hence, that implementation of hash is broken for any object > that does anything other than a pointer comparison in -isEqual:.
I thought we were talking about -hash just returning zero? --Kyle Sluder _______________________________________________ Cocoa-dev mailing list ([email protected]) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to [email protected]
