Rick:
The following code, which is likely what you are doing, will return the time in
1970 (NSDate's reference date) because you have not specified a date:
NSString *timeString = @"14:50 PDT";
NSDateFormatter *df = [[NSDateFormatter alloc ] init];
[df setDateFormat:@"HH':'mm zzz"];
NSDate *date = [df dateFromString:timeString];
[df release];
Instead, you need to use date components to set the day as well as the time,
per the following:
NSString *timeString = @"14:50 PDT";
NSDateFormatter *df = [[NSDateFormatter alloc ] init];
[df setDateFormat:@"HH':'mm zzz"];
NSDate *date = [df dateFromString:timeString];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *dateComponents = [calendar components:( NSYearCalendarUnit |
NSMonthCalendarUnit | NSDayCalendarUnit ) fromDate:[NSDate date]];
NSDateComponents *timeComponents = [calendar components:( NSHourCalendarUnit |
NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate: date ];
[dateComponents setHour:[timeComponents hour]];
[dateComponents setMinute:[timeComponents minute]];
[dateComponents setSecond:[timeComponents second]];
NSDate *timeToday = [calendar dateFromComponents:dateComponents];
[df release];
Change 'fromDate' in NSDateComponents *dateComponents to whatever date you want
in order to create your time on a different day.
Best Wishes.
Roger Dalal
On Oct 12, 2011, at 9:30 PM, Rick Mann wrote:
> I have a situation where I have to parse times like "14:50 PDT". If I just
> set up an NSDateFormatter with dateFormat = @"HH:mm z", I end up with a time
> of day in 1970.
>
> What's the best way to get it to give me that time of day today?
>
> Thanks,
> Rick
>
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