> [ array objectAtIndex:i ] doesn't create temporaries either.

OK, then that blew my logic right out of the water!
Thanks for clearing things up Roland :)


On 16 April 2012 10:53, Roland King <[email protected]> wrote:

> There are no temporary objects created during fast enumeration, you just
> get a reference to one of the objects in the thing you are enumerating.
>
> [ array objectAtIndex:i ] doesn't create temporaries either.
>
>
> On Apr 16, 2012, at 5:42 PM, Patrick Robertson wrote:
>
> > Hi all,
> >
> > I've searched the web, but can't seem to find any concrete information on
> > how fast enumeration loops manage temporarily created objects.
> > Would anybody be able to shine some light on whether fast enumeration
> > itself takes care of the objects it creates?
> >
> > So, for example in:
> >
> > for (id anObject in anArray) {
> > // do some stuff
> > }
> >
> > I'm assuming that the fast enumeration loop itself does something like
> this
> > behind the scenes for each object in the array:
> > id anObject = [anArray objectAtIndex:i]
> >
> > so are these temp objects created during the enumeration released
> > automatically at the end of the loop, or is it work wrapping the whole
> > thing in an autoreleasepool?
> >
> > @autoreleasepool {
> > for (id anObject in anArray) {
> > // do some stuff
> > }
> > }
> >
> > Thanks
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