On Sep 20, 2014, at 11:13 AM, 2551 <2551p...@gmail.com> wrote:
> For example:
>
> NSString *mary = @"mary had a little lamb, a little lamb she had";
> NSString *scary = @"mary had a little lamb, a little naughty fella of a
> lamb she had for sure";
> NSString *isDifferent = [self getDifference:mary and: scary];
> NSLog(@"%@", isDifferent);
>
> The method I posted below produces the difference that I want ("naughty fella
> of a for sure"). But I want to know if there's a more orthodox and robust
> solution.
>>>
I would use an NSOrderedSet and NSCharacterSet for robustness, e.g.:
NSMutableCharacterSet *separatorSet = [NSMutableCharacterSet
punctuationCharacterSet];
[separatorSet formUnionWithCharacterSet:[NSCharacterSet
whitespaceAndNewlineCharacterSet]];
NSMutableOrderedSet *maryWords = [NSMutableOrderedSet orderedSetWithArray:[mary
componentsSeparatedByCharactersInSet:separatorSet]];
NSMutableOrderedSet *scaryWords = [NSMutableOrderedSet
orderedSetWithArray:[scary componentsSeparatedByCharactersInSet:separatorSet]];
BOOL maryLonger = [maryWords count] > [scaryWords count];
[(maryLonger ? maryWords : scaryWords) minusOrderedSet:(maryLonger ? scaryWords
: maryWords)];
NSLog(@"%@", (maryLonger ? maryWords : scaryWords));
Though this wouldn't account for order or duplicates, but neither would your
implementation.
>>
>>> -(NSString *)getDifference: (NSString *)aString and:(NSString
>>> *)anotherString {
>>> int i = aString.length;
>>> int j = anotherString.length;
>>> NSString *result, *longest, *shortest;
>>>
>>> if (i == j) {
>>> result = @"";
>>> return result;
>>> }
>>>
>>> if (i > j) {
>>> longest = aString;
>>> shortest = anotherString;
>>> } else {
>>> longest = anotherString;
>>> shortest = aString;
>>> }
>>>
>>> NSArray *fa = [longest componentsSeparatedByString: @" " ];
>>> NSArray *sa = [shortest componentsSeparatedByString: @" "];
>>> NSMutableArray *remainder = [NSMutableArray arrayWithArray:fa];
>>> [remainder removeObjectsInArray:sa];
>>> result = [remainder componentsJoinedByString:@" "];
>>> return result;
>>>
>>> }
Keary Suska
Esoteritech, Inc.
"Demystifying technology for your home or business"
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