1. use the DirectoryGenerator as startpoint 2. use XSLT to transform the resulting XML to your wanted output, e.g. using document() to get the content of the specific tag
Regards, Joerg icewind wrote: > I would like to be able to have cocoon take an entire > directory of xml files, go through it, grab the > contents of some tag (a that all the xml documents in > this directory have) and output a page with the > following information for each document in that > directory: > > 1. The filename (linked to the file) > 2. The contents of the tag from the file > > > How would I do this? -- System Development VIRBUS AG Fon +49(0)341-979-7419 Fax +49(0)341-979-7409 [EMAIL PROTECTED] www.virbus.de --------------------------------------------------------------------- Please check that your question has not already been answered in the FAQ before posting. <http://xml.apache.org/cocoon/faq/index.html> To unsubscribe, e-mail: <[EMAIL PROTECTED]> For additional commands, e-mail: <[EMAIL PROTECTED]>
