Hi !! I worked with Tomcat 4.0.4, JDK 1.3.1_03 and Cocoon2.0.2 under W2000.
I want to use the Cocoon2.0.3 version. I installed it as describe in the "Installing Apache Cocoon" page. But when I test it I receive the following message : org.apache.cocoon.ProcessingException: Language Exception: org.apache.cocoon.components.language.LanguageException: Error compiling sitemap_xmap: Line 1210, column 84: invalid escape character Line 1214, column 40: invalid escape character Line 1261, column 84: invalid escape character Line 1265, column 40: invalid escape character Line 0, column 0: 4 errors Where could the problem come from ? How can I interprete the line number: 1210 doesn't exist in my sitemap... Why does my sitemap compile without error under Cocoon2.0.2 but not under Cocoon2.0.3 ? Thanks for the response... Please excuse me if a similar question/answer has been written... I haven't found it... Nicolas !! --------------------------------------------------------------------- Please check that your question has not already been answered in the FAQ before posting. <http://xml.apache.org/cocoon/faq/index.html> To unsubscribe, e-mail: <[EMAIL PROTECTED]> For additional commands, e-mail: <[EMAIL PROTECTED]>
