Thanks Ugo!
I know I have a really big problem, I am newbie in Java, XML, XSL and Cocoon
at the same time:
1-XML dont make me problem because is very easy.
2-Cocoon I think is very logical, but have some dark sides to me (I think).
3-For Java I need to have the API Docs in a browser to write something :(
4-With XSL I think I know now a little more, but always need to see or take
some code from the already Cocoon code. :(
My only strong is that I have a very very hard head. This is why I can stand
on the same problem many times, read some docs and try again and again until
it is done :)
Antonio Gallardo
El Jueves, 03 de Octubre de 2002 06:32, Ugo Cei escribió:
> Antonio Gallardo Rivera wrote:
> > if (i > 0)
> > {
> > a.concat("WHERE cat_id=");
> > a.concat(Integer.toString(i));
> > }
>
> Strings in Java are immutable! The concat(String) method returns a *NEW*
> String [1].
>
> a = a.concat("WHERE cat_id=");
> a = a.concat(Integer.toString(i));
>
> Or better yet, use a StringBuffer.
>
> Ugo
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