[EMAIL PROTECTED] wrote: > Thank you Steve, and sorry for my "beginner's question". > But by me: > > Here the line that start Tomcat in my startup.bat script: > > call "%_TC_BIN_DIR%\tomcat" start %1 %2 %3 %4 %5 %6 %7 %8 %9
hm - what version of tomcat is that? > which launch the tomcat.bat script with the parameter "start". > > You speak about a java command but it seems it is in the tomcat.bat script. there should be - perhaps using some JAVA_CMD variable that is defined in the beginning of your batch script > Should I modify the tomcat.bat? > I would prefer to modify the startup.bat! But what is the command in this case? > > I have also tried to add a "CATALINA_OPTS" environment variable with the value >"-Dhttp.proxyHost=http://proxy.blabla.com -Dhttp.proxyPort=8080" but that doesn't >work. Maybe a proxy access problem?!? Have you tried TOMCAT_OPTS? Catalina = Tomcat version 4. </Steven> -- Steven Noels http://outerthought.org/ Outerthought - Open Source, Java & XML Competence Support Center [EMAIL PROTECTED] [EMAIL PROTECTED] --------------------------------------------------------------------- Please check that your question has not already been answered in the FAQ before posting. <http://xml.apache.org/cocoon/faq/index.html> To unsubscribe, e-mail: <[EMAIL PROTECTED]> For additional commands, e-mail: <[EMAIL PROTECTED]>
