Hi all,
I am a newbie with cocoon. I've got some troubles and hope you can help me.
I've got an XML-File, its DTD and an XSL-File. I think they are all
well-formed and valid.
In the XML-File I declared:
Cocoon-process-type: <?cocoon process type="xslt"?>
the Stylesheet location: <?xml stylesheet href="energiebericht.xsl?
type="text/xsl"?>
the doctype: <!DOCTYPE energiebericht SYSTEM
"energiebericht.dtd">
In the XSL-File I declared:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="energien" match="energietraeger" use="beschreibung"/>
I use:
cocoon 2.0.4
jakarta tomcat 4.1.12
jdk 1.3.1
now I want to try to look view my XML-file in the browser
(http://localhost:8080/cocoon/energie/energiebericht-70-99.xml)
and I get following error:
Cocoon 2 - Resource not found
------------------------------------------------------------------------
type resource-not-found
messageResource not found
descriptionThe requested URI "/cocoon/energie/energiebericht-70-99.xml"
was not found.
sender org.apache.cocoon.servlet.CocoonServlet
source Cocoon servlet
request-uri
/cocoon/energie/energiebericht-70-99.xml
path-info
energie/energiebericht-70-99.xml
What's wrong?
Thanks for any advice
Sorin Marti
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- Re: Transforming XML with XSL and Cocoon Sorin Marti