Re: XMLForm: how to retrieve URL parameter?

[Lionel Crine]

You can also see the source of the request generator.

It's almost the same thing....look the setup method.

Lionel

At 23:15 31/03/2003 +0200, you wrote:
Sure:

public Map act (Redirector redirector, SourceResolver resolver,
    Map objectModel, String source, Parameters params) throws
java.lang.Exception {
Map resultMap = super.act(redirector, resolver, objectModel, source,
params);
Request request = (Request) objectModel.get(Constants.REQUEST_OBJECT);
//I think you can also write the above line this way:
//Request request = ObjectModelHelper.getRequest(objectModel);
String the_parameter = request.getParameter("the_parameter");
...
I do not know if easier ways exist but this worked for me.
Hope it helps.
----- Original Message -----
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, March 31, 2003 2:07 PM
Subject: RE: XMLForm: how to retrieve URL parameter?
> Hi again,
>
> Could you give an example of your code?
>
> Thanks
> Sylvain
>


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