On Thu, Oct 13, 2016 at 3:18 PM, Jugraj Singh <[email protected]> wrote: <snip> > > This is the code around line 75 > 73 for (String phoneContact : phoneContacts) { > 74 Contact contact = Display.getInstance().getContactById(phoneContact); > 75 Hashtable<String, String> temp = new Hashtable<>(); > 76 temp.put("phone",contact.getPrimaryPhoneNumber()); > 77 temp.put("name",contact.getDisplayName()); > 78 con.add(temp); > 79 } > > I did not see anything wrong there. > The exception i getting is null pointer value == null but i initialise the temp variable here.
-- Jugraj Singh git :- https://github.com/jugrajsingh blog :- ezecodes.wordpress.com "If all you have is a hammer, everything looks like a nail" -- You received this message because you are subscribed to the Google Groups "CodenameOne Discussions" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. Visit this group at https://groups.google.com/group/codenameone-discussions. To view this discussion on the web visit https://groups.google.com/d/msgid/codenameone-discussions/CACSuXDrbeOGQV7-upjU_i4wVHsMd7PhKu1DfFUSF5-CJYCt%2BnQ%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.
