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https://issues.apache.org/jira/browse/CASSANDRA-12621?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Alex Petrov updated CASSANDRA-12621:
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Priority: Minor (was: Critical)
> How to query '%' character using LIKE operator in Cassandra 3.7?
> ----------------------------------------------------------------
>
> Key: CASSANDRA-12621
> URL: https://issues.apache.org/jira/browse/CASSANDRA-12621
> Project: Cassandra
> Issue Type: Bug
> Reporter: Mikhail Krupitskiy
> Priority: Minor
> Labels: sasi
>
> I use Cassandra 3.7 and have a text column with SASI index. Let's assume that
> I want to find column values that contain '%' character somewhere in the
> middle. The problem is that '%' is a command char for LIKE clauses. How to
> escape '%' char in a query like LIKE '%%%'?
> Here is a test script:
> {code}
> DROP keyspace if exists kmv;
> CREATE keyspace if not exists kmv WITH REPLICATION = { 'class' :
> 'SimpleStrategy', 'replication_factor':'1'} ;
> USE kmv;
> CREATE TABLE if not exists kmv (id int, c1 text, c2 text, PRIMARY KEY(id,
> c1));
> CREATE CUSTOM INDEX ON kmv.kmv ( c2 ) USING
> 'org.apache.cassandra.index.sasi.SASIIndex' WITH OPTIONS = {
> 'analyzed' : 'true',
> 'analyzer_class' :
> 'org.apache.cassandra.index.sasi.analyzer.NonTokenizingAnalyzer',
> 'case_sensitive' : 'false',
> 'mode' : 'CONTAINS'
> };
> INSERT into kmv (id, c1, c2) values (1, 'f22', 'qwe%asd');
> SELECT c2 from kmv.kmv where c2 like '%$$%$$%';
> {code}
> The select query returns nothing.
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