flozano commented on issue #5925:
URL:
https://github.com/apache/incubator-kie-drools/issues/5925#issuecomment-2107350075
from byte-buddy, it very explicitly supports subclasses of generic parents:
```java
/**
* <p>
* Creates a new builder for subclassing the provided type. If the
provided type is an interface, a new class implementing
* this interface type is created.
* </p>
* <p>
* When extending a class, Byte Buddy imitates all visible constructors
of the subclassed type and sets them to be {@code public}.
* Any constructor is implemented to only invoke its super type
constructor of equal signature. Another behavior can be specified by
* supplying an explicit {@link ConstructorStrategy} by {@link
ByteBuddy#subclass(TypeDefinition, ConstructorStrategy)}.
* </p>
* <p>
* <b>Note</b>: This methods implements the supplied types <i>as is</i>,
i.e. any {@link TypeDescription} values are implemented
* as raw types if they declare type variables.
* </p>
* <p>
* <b>Note</b>: Byte Buddy does not cache previous subclasses but will
attempt the generation of a new subclass. For caching
* types, a external cache or {@link TypeCache} should be used.
* </p>
*
* @param superType The super class or interface type to extend. The
type must be a raw type or parameterized type. All type
* variables that are referenced by the generic type
must be declared by the generated subclass before creating
* the type.
* @return A type builder for creating a new class extending the
provided class or interface.
*/
public DynamicType.Builder<?> subclass(TypeDefinition superType) {
return subclass(superType,
ConstructorStrategy.Default.IMITATE_SUPER_CLASS_OPENING);
}
```
`superType The super class or interface type to extend. The type must be a
raw type or parameterized type. All type variables that are referenced by the
generic type must be declared by the generated subclass before creating the
type.`
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