hzfan commented on a change in pull request #15851: [Numpy] Numpy copysign
URL: https://github.com/apache/incubator-mxnet/pull/15851#discussion_r324475346
##########
File path: tests/python/unittest/test_numpy_op.py
##########
@@ -1853,6 +1853,111 @@ def hybrid_forward(self, F, x):
assert_almost_equal(mx_ret.asnumpy(), np_ret, atol=1e-5,
rtol=1e-4)
+@with_seed()
+@use_np
+def test_np_copysign():
+ class TestCopysign(HybridBlock):
+ def __init__(self):
+ super(TestCopysign, self).__init__()
+
+ def hybrid_forward(self, F, a1, a2):
+ return F.np.copysign(a1, a2)
+
+ def get_grad(a1, a2):
+ sign = _np.logical_or(_np.logical_and(a1 < 0, a2 < 0),
+ _np.logical_and(a1 >= 0, a2 >= 0))
+ sign = 2 * sign.astype(int) - 1
+ sign = sign.reshape(-1, *a1.shape)
+ sign = _np.sum(sign, axis=0)
+ return sign, _np.zeros_like(a2)
+
+ def get_grad_left(a1, a2):
+ sign = _np.logical_or(_np.logical_and(a1 < 0, a2 < 0),
+ _np.logical_and(a1 >= 0, a2 >= 0))
+ sign = 2 * sign.astype(int) - 1
+ sign = sign.reshape(a1.shape)
+ return sign
+
+ def get_grad_right(a1, a2):
+ return _np.zeros_like(a2)
+
+ shapes = [
+ (),
+ (1),
+ (2, 1),
+ (3, 2, 1),
+ (4, 3, 2, 1),
+ (2, 4, 3, 2, 1)
+ ]
+ types = ['float16', 'float32', 'float64', 'int8', 'int32', 'int64']
+ for a1shape in shapes:
+ for a2shape in shapes:
+ for hybridize in [True, False]:
+ for dtype in types:
+ test_copysign = TestCopysign()
+ if hybridize:
+ test_copysign.hybridize()
+ rtol = 1e-3
+ atol = 1e-5
+ a1_np = _np.array(_np.random.uniform(-1.0, 1.0, a1shape),
dtype=dtype)
+ a2_np = _np.array(_np.random.uniform(-1.0, 1.0, a2shape),
dtype=dtype)
+ a1 = np.array(a1_np, dtype=dtype)
+ a2 = np.array(a2_np, dtype=dtype)
+ a1.attach_grad()
+ a2.attach_grad()
+ expected_np = _np.copysign(a1_np, a2_np)
+ with mx.autograd.record():
+ mx_out = test_copysign(a1, a2)
+ assert mx_out.shape == expected_np.shape
Review comment:
I agree that in the future we should do it, after more dtypes and casting is
supported.
----------------------------------------------------------------
This is an automated message from the Apache Git Service.
To respond to the message, please log on to GitHub and use the
URL above to go to the specific comment.
For queries about this service, please contact Infrastructure at:
[email protected]
With regards,
Apache Git Services