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new 1be841fd7 [ISSUE #484] Fix 09subscription.md en document code error
and translate some Chinese into English (#485)
1be841fd7 is described below
commit 1be841fd71778a014823d0172d05cdad945c40a4
Author: mxsm <[email protected]>
AuthorDate: Mon Jan 30 11:29:28 2023 +0800
[ISSUE #484] Fix 09subscription.md en document code error and translate
some Chinese into English (#485)
---
.../version-5.0/03-domainModel/09subscription.md | 8 ++++----
1 file changed, 4 insertions(+), 4 deletions(-)
diff --git
a/i18n/en/docusaurus-plugin-content-docs/version-5.0/03-domainModel/09subscription.md
b/i18n/en/docusaurus-plugin-content-docs/version-5.0/03-domainModel/09subscription.md
index 05e7395cd..13ce6f39f 100644
---
a/i18n/en/docusaurus-plugin-content-docs/version-5.0/03-domainModel/09subscription.md
+++
b/i18n/en/docusaurus-plugin-content-docs/version-5.0/03-domainModel/09subscription.md
@@ -19,10 +19,10 @@ By configuring subscriptions, you can control the following
messaging behaviors:
The subscriptions of Apache RocketMQ are designed based on consumer groups and
topics. Therefore, a subscription refers to the subscription of a specified
consumer group to a topic. The following describes the rules for determining a
subscription:
* One topic to many subscribersThe following figure shows two consumer groups
(Group A and Group B) subscribed to Topic A. These two subscriptions are
independent of each other and can be defined separately.
- 
+ 
* One subscriber to multiple topicsThe following figure shows a consumer group
(Group A) subscribed to two topics: Topic A and Topic B. Consumers in Group A
have two separate subscriptions to Topic A and Topic B. The two subscriptions
are independent of each other and can be defined separately.
- 
+ 
@@ -72,7 +72,7 @@ Apache RocketMQ manages subscriptions based on consumer
groups. Therefore, consu
c1.subscribe(topicA,"TagA");
//Consumer c2
Consumer c2 = ConsumerBuilder.build(groupA);
- c1.subscribe(topicA,"TagA");
+ c2.subscribe(topicA,"TagA");
```
@@ -85,7 +85,7 @@ Apache RocketMQ manages subscriptions based on consumer
groups. Therefore, consu
c1.subscribe(topicA,"TagA");
//Consumer c2Consumer
c2 = ConsumerBuilder.build(groupA);
- c1.subscribe(topicA,"TagB");
+ c2.subscribe(topicA,"TagB");
```
## Usage notes