I would suggest something more like this:

    public static void main(String[] args) throws Exception {

            String strURL = "http://201.173.335.213/xxxx/xxxxx";;

            PostMethod post = new PostMethod(strURL);

            inputXML();

            post.setRequestBody("inputXml="+sbInputXML.toString());

            post.setRequestHeader("Content-type", "text/xml");

            HttpClient hc = new HttpClient();
            int iResultCode = hc.executeMethod(post);
            post.releaseConnection();
    }

Mike

Divakar Satyanarayan wrote:
Yes I made some modification & below is my code.

I have got it working with the following code but request is getting timed
out.

public static void main(String[] args) throws Exception
{

String strURL = "http://201.173.335.213/xxxx/xxxxx";;

String strHost = "201.173.335.213";

URL u = new URL("http://"+strURL);


PostMethod post = new PostMethod(strURL);

inputXML();

post.setRequestBody("inputXml="+sbInputXML.toString());


if ((u.getPath() == null) || (u.getPath().length() == 0)) {
post.setPath("/");
}
else {
post.setPath(u.getPath());
}

System.out.println("THe Path is " +post.getPath() );

post.setRequestHeader("Content-type", "text/xml");

System.out.println("THe Object 3 ");
/*
HttpConnection oHttpConnection = new
HttpConnection(strURL,440); oHttpConnection.open();*/

//HttpClient hc = new
HttpClient(oHttpConnection.getHttpConnectionManager());

HttpClient hc = new HttpClient();

System.out.println(" About to configure ");

/*HostConfiguration cfg = new HostConfiguration();

System.out.println(" Configured Host ");

// cfg.setHost(new URI(u));

cfg.setHost(strHost,440,"http");
System.out.println("THe Host "+cfg.getHost());

System.out.println("THe Host URL "+cfg.getHostURL());
System.out.println("THe Protocol "+cfg.getProtocol());

System.out.println("Is Host Set "+cfg.isHostSet());

System.out.println("Client Uses Port "+hc.getPort());


*/
int iResultCode = hc.executeMethod(post);

System.out.println("iResultCode = " + iResultCode);

System.out.println("Server response:" +
post.getResponseBodyAsString() );

post.releaseConnection();
}



-----Original Message-----
From: Michael Becke [SMTP:[EMAIL PROTECTED]]
Sent: Friday, January 31, 2003 8:51 PM
To: Commons HttpClient Project
Subject: Re: java.net.UnknownHostException

Are you using the most recent code from CVS? I just tried this example and it worked for me. Did you make any changes to the example?

Mike

Divakar Satyanarayan wrote:

The first thing I did was to run the sample code PostXML.java. But it
gave

me a run time exception
Exception in thread "main" java.lang.IllegalArgumentException: host
parameter is null
at

org.apache.commons.httpclient.HttpConnection.<init>(HttpConnection.java:21
7)

       at

org.apache.commons.httpclient.HttpConnection.<init>(HttpConnection.java:14
5)

       at

org.apache.commons.httpclient.SimpleHttpConnectionManager.getConnection(Si
mp

leHttpConnectionManager.java:118)
       at

org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:541
)

       at

org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:474
)

       at PostXML.main(PostXML.java:268)

Once the host configuration is done I could see the host & port to
which it

is configured. But I am puzzled by the above exception when
exceuteMethod is

invoked.
Are there any leads to the solution for the above problem.

Divakar




-----Original Message-----
From: Michael Becke [SMTP:[EMAIL PROTECTED]]
Sent: Friday, January 31, 2003 7:36 PM
To: Commons HttpClient Project
Subject: Re: java.net.UnknownHostException

Please take a look at the following URL as an example of how to use HttpClient to read from a server:

http://cvs.apache.org/viewcvs/jakarta-commons/httpclient/src/examples/ BasicAuthenticatonExample.java?rev=1.3&content-type=text/vnd.viewcvs- markup

It seems that the problem is that you are attempting to read directly

from an HttpConnection. Though this seems logical given how the

java.net.UrlConnection works, HttpClient handles things a little differently. All posts, gets, etc. are done via HttpMethods like PostMethod and GetMethod. HttpConnection is not meant to be used directly.

Mike

On Friday, January 31, 2003, at 07:32 AM, Divakar Satyanarayan wrote:



Hi,

I am using HTTPConnection to get a connection to an URL. It works fine when
I give just the IP address but when I specify the full path it gives me
following exception

java.net.UnknownHostException: 201.173.335.213/xxxx/xxxxx
at java.net.InetAddress.getAllByName0(InetAddress.java:571)
at java.net.InetAddress.getAllByName0(InetAddress.java:540)
at java.net.InetAddress.getByName(InetAddress.java:472)
at java.net.Socket.<init>(Socket.java:100)
at
org.apache.commons.httpclient.protocol.DefaultProtocolSocketFactory.cre

ateSo
cket(DefaultProtocolSocketFactory.java:104)
      at
org.apache.commons.httpclient.HttpConnection.open(HttpConnection.java:4

88)
      at TrialConnectionClient.main(TrialConnectionClient.java:237).

What am I missing ? I've pasted the code

			HttpConnection oHttpConnection = new
HttpConnection(strURL,440);

			logMessage("Connected before"+
oHttpConnection.isOpen() );
			
			logMessage("Connected before"+
oHttpConnection.getProxyHost());

			logMessage("Connected before"+
oHttpConnection.getPort());	
			
			oHttpConnection.open();

			logMessage("Connected after"+
oHttpConnection.isOpen() );
			
			RequestOutputStream oRequestOutputStream = new
RequestOutputStream(oHttpConnection.getRequestOutputStream(),false);
			
			logMessage("Output Stream ");

			strXml = "inputXml="+sbInputXML.toString();

			oRequestOutputStream.println(strXml);
			//oRequestOutputStream.close();
			
			logMessage(" Input Stream ");
			
			
			
			BufferedReader oBufferedReader = new
BufferedReader(new
InputStreamReader(oHttpConnection.getResponseInputStream()));
			
			logMessage("Opening the input Stream");
			
			String line;
			
			System.out.println(System.currentTimeMillis());

			logMessage("Buffered Input starting to read");

			while ((line = oBufferedReader.readLine()) != null)
			{
				System.out.println(line);
				sbXMLText.append(line + "\n");
			}
		




Regards,
Divakar
___________________________
DIVAKAR SATYANARAYAN
+91-80-5521701-6 Ext : 1018




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