Re: [digester] how to make use of xml:lang?

[Craig R. McClanahan]

Simon Kitching wrote:

On Tue, 2003-10-21 at 10:57, Craig R. McClanahan wrote:

 

But you could certainly supply your own Rule (no trailing "s") 
implementation whose begin() method checked the Attributes that are 
passed to see which (if any) xml:lang attribute was set.

Craig
   

Hmm .. so

digester.addRule ( 
   "obj/attr",
   new LangFilterRule("en",
     new CallMethodRule(....));

digester.addRule ( 
   "obj/attr",
   new LangFilterRule("en",
     new CallParamRule(....));

digester.addRule ( 
   "obj/attr",
   new LangFilterRule("fr",
     new CallMethodRule(....));

digester.addRule ( 
   "obj/attr",
   new LangFilterRule("fr",
     new CallParamRule(....));

Looks pretty cumbersome to me. Doable, but cumbersome.

Depends how many language-sensitive rules there are, I guess.

It would certainly be nicer to say:
 digester.setLanguage("fr")
or
 digester.getRules().setLanguage("fr")
Hmm... maybe the solution is instead to write a SAX filter that filters
out any elements with undesirable lang settings?????
 

I'd be -1 on trying to make anything in the generic rules dependent 
*solely* on xml:lang, instead of being able to be dependent on some 
other arbitrary attribute.

If it were up to me, I wouldn't build conditionality into the Digester 
rules in the first place -- I'd build it into the object that receives a 
completed object and ignores it if it doesn't want that instance.  But 
that's just me ...

Ricky: note that Digester implements org.xml.sax.ContentHandler, ie you
can create a SAX parser object yourself and set a Digester instance as
the content handler for that parser (this is all Digester's parse method
does internally). So you could:
(a) create a SAXParser instance
(b) create an org.xml.sax.XMLFilter instance which removes all undesired
elements and passes the remainder to the Digester instance.
Hope this helps,

Simon

 

Craig

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