System.getProperty are protected, I will have to change the access Control policy : java.security.AccessControlException: access denied (java.util.PropertyPermission http.proxyHost read)
Another way, will be to instantiate an UrlConnection and get back the proxy parameters. But, I think that it is not very pretty.
Thanks for your help.
Laurent For�t
[EMAIL PROTECTED] wrote:
Laurent, I will be more than happy to help you as far as HttpClient is concerned, but I have always shunned away from applet programming at all costs, and therefore can be of little assistence here. I _suppose_ if the browser is equipped with the Sun's Java plugin, you _may_ be able to query the http.proxyHost and http.proxyPort system properties. But this is no more than a wild guess on my part.
Cheers,
Oleg
-- Original Message -- Reply-To: "Jakarta Commons Users List" <[EMAIL PROTECTED]> Date: Fri, 19 Mar 2004 16:20:09 +0100 From: Laurent For�t <[EMAIL PROTECTED]> To: Jakarta Commons Users List <[EMAIL PROTECTED]> Subject: Re: [HTTPClient] How to use the cookie JSessionID ... becomes
How
to pass clien
Ok Great !!! thanks a lot, it seems to work now !
Now, I am coming back to my initial problem. If I want to initialize my applet transparently, I need to get all these parameters from my client.
Is there anyway to do this, in javascript ?
I can not decently asked to the customer each time these 4 parameters.
Laurent F
[EMAIL PROTECTED] wrote:
Laurent. One little detail is missing. HttpClient still does not know you want
to
go through the proxy.
Just add one extra configuration line right after HttpClient instantiation
HttpClient client = new HttpClient(); client.getHostConfiguration().setProxy(PROXY_IP, PROXY_PORT);
In order to be able to see what exactly HttpClient is doing you may want to turn the wire/debug log when troubleshooting problems
<http://jakarta.apache.org/commons/httpclient/logging.html>
HTH
Oleg
-- Original Message -- Reply-To: "Jakarta Commons Users List" <[EMAIL PROTECTED]> Date: Fri, 19 Mar 2004 15:26:55 +0100 From: Laurent For�t <[EMAIL PROTECTED]> To: Jakarta Commons Users List <[EMAIL PROTECTED]> Subject: Re: [HTTPClient] How to use the cookie JSessionID ... becomes
How
to pass client proxy Authorization through applet.
I begin to understand how proxy works, now. And I think now that my previous question was stupid.
This morning, I have configured a squid proxy with user authorization
and
a firewall with which the only possible connection to the web is through this proxy.
I try the simplest program using proxy HttpClient, inspired from cvs example :
static String PROXY_IP = "195.46.214.114"; static String PROXY_USER = "squid"; static String PROXY_PASSWORD = "squid";
public static void main(String[] args) throws Exception { HttpClient client = new HttpClient(); //client.getState().setAuthenticationPreemptive(true); client.getState().setAuthenticationPreemptive(true);
client.getState().setProxyCredentials( // IP_PROXY, null, IP_PROXY, new UsernamePasswordCredentials(PROXY_USER, PROXY_PASSWORD) );
System.out.println(client.getState().toString());
GetMethod get = new GetMethod("http://www.google.com";); get.setDoAuthentication( true ); try { int status = client.executeMethod( get ); System.out.println(status + "\n" + get.getResponseBodyAsString()); } finally { get.releaseConnection(); } }
This program ignore the proxyCredentials. And try to connect directly
with
failure (due to the firewall) to www.google.com
What I have done wrong ?
I am discouraged !!
Laurent F.
PS the output :
[Authentication domain: '195.46.214.114', authentication realm: 'null'#squid:squidUser
| Authentication domain: '195.46.214.114', authentication realm: 'null'#squid:squidUser
| ]
java.net.SocketException: connect (code=10004)
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:320)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:133)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:120)
at java.net.Socket.<init>(Socket.java:273)
at java.net.Socket.<init>(Socket.java:100)
at org.apache.commons.httpclient.protocol.DefaultProtocolSocketFactory.createSocket(DefaultProtocolSocketFactory.java:118)
at org.apache.commons.httpclient.HttpConnection.open(HttpConnection.java:683)
at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:662)
at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:529)
at com.clipack.lfo.TestAuthentication.main(TestAuthentication.java:37)
Laurent For�t wrote:
Ok, thanks a lot. I am sorry, I haven't seen that credentials was also
for Proxy Authentication.
Another question, I hope it will be the last ;) :
How do we know the values of String parameters for the UsernamePasswordCredentials constructor ?
Is it better to use the default ?
Thanks again for all your help.
Laurent F.
Oleg Kalnichevski wrote:
On Thu, 2004-03-18 at 16:49, Laurent For�t wrote:
My problem is now,
how to pass througn proxy Authorization using httpClient. Is it managed by HttpClient, or do we have to provide code to manage
?
If it is the case , how ?
HttpClient does provide support for transparent proxy authentication. All you have to do is to add the required proxy credentials to the HttpState used by HttpClient. Please refer to the javadocs for details
Oleg
Thanks in advance.
Laurent F.
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